For this case we must find the product of the following expressions:
\frac {3x} {x + 1} * \frac {x} {x-7}
So:
\frac {3x ^ 2} {x ^ 2-7x + x-7} =\\\frac {3x ^ 2} {x ^ 2-6x-7}
So, we have to:
\frac {3x} {x + 1} * \frac {x} {x-7} = \frac {3x ^ 2} {x ^ 2-6x-7}
Answer:
\frac {3x ^ 2} {x ^ 2-6x-7}
Step-by-step explanation:
