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NEED HELP PLEASE!! WILL GIVE A MEDAL!!

Given the function f(x) = 4(2)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.

Part A: Find the average rate of change of each section. [I think its 8 and 32]

Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. 

Respuesta :

caylus
Hello,

Part A:

f(2)=4*2²=16
f(1)=4*2^1=8
2-1=1
(f(2)-f(1))/(2-1)=(16-8)/1=8 ; r_1=8

f(3)=4*2^3=32
f(4)=4*2^4=64
(f(4)-f(3))/(4-3)=(64-32)/1=32 ; r_2=32

Part B:
r_2=32=4*8=4*r_1

Explainations:

(4*2^2-4*2^1)/(2-1)=4*2^1(2-1)=4*2
(4*2^4-4*2^3)/(4-3)=4*2^3*(2-1)=4*8=(4*2)*4



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