Respuesta :

Answer:

[tex]x=\left \{ {{10+\sqrt{59}} \atop {10-\sqrt{59}}} \right.[/tex]

Step-by-step explanation:

[tex]x^2-20x+41=0[/tex]

[tex](x-10)^2-10^2+41=0[/tex]

[tex](x-10)^2-59=0[/tex]

[tex](x-10)^2=59[/tex]

[tex](x-10)=\left \{ {{\sqrt{59}} \atop {-\sqrt{59}}} \right[/tex]

[tex]x=\left \{ {{10+\sqrt{59}} \atop {10-\sqrt{59}}} \right.[/tex]