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A 5.0-g bullet leaves the muzzle of a rifle with a speed of 320 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.82-m-long barrel of the rifle?

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opudodennis

Answer:

312.195 N

Explanation:

We know that the product of force and distance equals energy. In this case, it is equal to kinetic energy of the bullet. Since we have mass of bullet as 5g or 0.005 kg and velocity as 320 m/s then we can get energy. The distance here is given as 0.82 m

[tex]0.82F= 0.5\times 0.005\times 320^{2}\\F=312.195 N[/tex]

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