Answer:
two solutions : (-3;-6) , (5;10)
Step-by-step explanation:
hello :
the system is : y= 2x .....(*)
y= x2 - 15 ....(**)
put the value of y use (*) in (**) :
2x = x² - 15
x²-2x-15 = 0
(x+3)(x-5)=0
x+3 =0 or x-5=0
x= -3 or x= 5
case 1 : x= -3 y = 2(-3) = -6
case 2 : x=5 y = 2(5) = 10
two solutions : (-3;-6) , (5;10)