Explanation:
We know that relation between change in temperature and molality is as follows.
[tex]\Delta T = m \times k_{b}[/tex]
And, boiling point of a solution is calculated as follows.
Boiling point of a solution = Boiling point + [tex]\Delta T (k_{c} \times m)[/tex]
For benzene solution, the boiling point is 80.1 + 2.53m.
For [tex]CCl_{4}[/tex] solution, the boiling point is 76.8 + 5.03m
Now, equating the boiling point of both the solutions as follows.
80.1 + 2.53m = 76.8 + 5.03m
3.3 = 2.5 m
m = 1.32 mol of solute per kg of solvent
Therefore, the boiling point will be calculated as follows.
80.1 + 2.53m
[tex]80.1 + 2.53 \times 1.32[/tex]
= [tex]83.43^{o}C[/tex]
Thus, we can conclude that molal concentration (m) is 1.32 and boiling point is [tex]83.43^{o}C[/tex].
