Answer:
Mean 24, standard error 0.8
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sample means with size n of at least 30 can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation, also called standard error [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
In this problem, we have that:
[tex]\mu = 24, \sigma = 6.4, n = 64[/tex]
What are the mean and the standard error of the sample mean?
By the Central Limit Theorem, mean 24 and standard error [tex]s = \frac{6.4}{\sqrt{64}} = 0.8[/tex]
