JozsefG
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The dimensions of a room are: height = 4x-5 meters, length = 3x+1 meters, and width = 2x-3 meters. What is the volume of the room?

Respuesta :

opudodennis

Answer:

[tex](24x^2-58x^2-43x+15)m^3[/tex]

Step-by-step explanation:

Volume is given by the product of an object's three dimensions, length by height by width.

Now given the dimensions as:height = 4x-5 meters, length = 3x+1 meters, and width = 2x-3 meters, volume is calculated as:

[tex]V=lwh\\=(4x-5)(3x+1)(2x-3)\\=(12x^2-11x-5)(2x-3)\\=(24x^3-36x^2-22x^2-33x-10x+15)\\=(24x^2-58x^2-43x+15)m^3[/tex]

Hence, the volume of the room is [tex](24x^2-58x^2-43x+15)m^3[/tex]

shristiparmar1221

This question is based on the volume of cuboid. Therefore, the volume of the given object as [tex]24x^3-58x^2-43x+15 \, m^3[/tex].

Given;

Height = 4x-5 meters, length = 3x+1 meters, and width = 2x-3 meters

According to the question,

Volume of an object's three dimensions,is defined as the product length, height and width.

The dimensions as : height = 4x-5 meters, length = 3x+1 meters, and width = 2x-3 meters.

[tex]Volume = length \times width\times height[/tex]

[tex]Volume = (4x-5) \times (3x+1) \times (2x-3)\\Volume =( 12x^2-11x - 5 )( 2x -3 )\\Volume = 24x^3 - 36x^2-22x^2 +33x -10x +15\\Volume = 24x^3-58x^2-43x+15 \, m^3[/tex]

Therefore, the volume of the given object as [tex]24x^3-58x^2-43x+15 \, m^3[/tex].

For more details, prefer this link;

https://brainly.com/question/24904892

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