Answer:
D. [tex]x=-(y+12)^2+5[/tex]
Step-by-step explanation:
A parabola that opens to the left has the equation
[tex](y-y_0)^2=-2p(x-x_0),[/tex]
where [tex](x_0,y_0)[/tex] is the vertex.
If the vertex of the parabola is at the point (5,-12), then its equation is
[tex](y-(-12))^2=-2p(x-5)\\ \\(y+12)^2=-2p(x-5)[/tex]
When [tex]p=\frac{1}{2},[/tex] the equation is
[tex](y+12)^2=-(x-5)\\ \\(y+12)^2=-x+5\\ \\x=-(y+12)^2+5[/tex]
