mlsamuel mlsamuel
  • 06-07-2016
  • Chemistry
contestada

How many moles of MgS2O3 are in 167 g of the compound?

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Willchemistry
Willchemistry Willchemistry
  • 06-07-2016
Molar mass MgS₂O₃ = 24 + 32 x 2 + 16 x 3 = 136 g/mol

1 mole ---------------- 136 g
? mole --------------- 167 g

moles = 167 x 1 / 136

moles = 167 / 136

= 1.227 moles of MgS₂O₃

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