The mass of the Mars is about 0.11 the mass of the earth, its radius is 0.53 that of the earth, and the acceleration due to gravity at the earth's surface is 9.80m/s^2 .1. Without looking up either body's mass, use this information to compute the acceleration due to gravity on the Mars's surface.

Question

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Respuesta :

opudodennis opudodennis · Answer 1 · 2020-03-18T09:59:03+01:00

Answer:

[tex]3.8377m/s^2[/tex]

Explanation:

The force due to gravity on earth's surface on mass [tex]m[/tex] is:

[tex]F=GMm/R^2[/tex]

Where,

F = GMm/R2

F = Gravitational Force

G = Gravitational Constant

M = Earth's Mass

m = mass of body

R = Earth's radius

The acceleration is F/m:

[tex]g=F/m=GM/R^2[/tex]

For a planet with 0.11M and 0.53R:

[tex]a=G(0.11M)/(0.53R)^2\\=0.3915g\ \ \ \ \ \ \g=9.8m/s^2\\=0.3915\times9.8m/s^2\\\\=3.8377m/s^2[/tex]

Hence gravity on Mar's surface is 3.8377[tex]m/s^2[/tex]