Answer : The amount energy needed is, 0.9 cal
Solution :
Formula used :
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
where,
Q = heat required = ?
m = mass of copper = 10 g
c = specific heat of copper = [tex]0.09cal/g^oC[/tex]
[tex]\Delta T=\text{Change in temperature}[/tex]
[tex]T_{final}[/tex] = final temperature = [tex]21^oC[/tex]
[tex]T_{initial}[/tex] = initial temperature = [tex]20^oC[/tex]
Now put all the given values in the above formula, we get :
[tex]Q=10g\times 0.09cal/g^oC\times (21-20)^oC[/tex]
[tex]Q=0.9cal[/tex]
Therefore, the amount energy needed is, 0.9 cal
