Respuesta :
Answer:
a)If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.
b)If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.
c)If concentration of [tex][H^+][/tex] is changed to 0.0001 M than rate will be increased by the factor of 0.01.
d) If concentration when [sucrose] and[tex][H^+][/tex] both are changed to 0.1 M than rate will be increased by the factor of 1.
Explanation:
Sucrose + [tex]H^+\rightarrow [/tex] fructose+ glucose
The rate law of the reaction is given as:
[tex]R=k[H^+][sucrose][/tex]
[tex][H^+]=0.01M[/tex]
[sucrose]= 1.0 M
[tex]R=k[0.01M][1.0 M][/tex]..[1]
a)
The rate of the reaction when [Sucrose] is changed to 2.5 M = R'
[tex]R'=[0.01 M][2.5 M][/tex]..[2]
[2] ÷ [1]
[tex]\frac{R'}{R}=\frac{[0.01 M][2.5 M]}{k[0.01M][1.0 M]}[/tex]
[tex]R'=2.5\times R[/tex]
If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.
b)
The rate of the reaction when [Sucrose] is changed to 0.5 M = R'
[tex]R'=[0.01 M][0.5 M][/tex]..[2]
[2] ÷ [1]
[tex]\frac{R'}{R}=\frac{[0.01 M][0.5 M]}{k[0.01M][1.0 M]}[/tex]
[tex]R'=2.5\times R[/tex]
If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.
c)
The rate of the reaction when [tex][H^+][/tex] is changed to 0.001 M = R'
[tex]R'=[0.0001 M][1.0 M][/tex]..[2]
[2] ÷ [1]
[tex]\frac{R'}{R}=\frac{[0.0001 M][1.0M]}{k[0.01M][1.0 M]}[/tex]
[tex]R'=0.01\times R[/tex]
If concentration of [tex][H^+][/tex] is changed to 0.0001 M than rate will be increased by the factor of 0.01.
d)
The rate of the reaction when [sucrose] and[tex][H^+][/tex] both are changed to 0.1 M = R'
[tex]R'=[0.1M][0.1M][/tex]..[2]
[2] ÷ [1]
[tex]\frac{R'}{R}=\frac{[0.1M][0.1M]}{k[0.01M][1.0 M]}[/tex]
[tex]R'=1\times R[/tex]
If concentration when [sucrose] and[tex][H^+][/tex] both are changed to 0.1 M than rate will be increased by the factor of 1.