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In 1962, measurements of the magnetic field of a large tornado weremade at the Geophysical Observatory in Tulsa, Oklahoma. If themagnitude of the tornado's field was B = 16.50 nT pointing north when the tornado was8.10 km east of the observatory, whatcurrent was carried up or down the funnel of the tornado?

Respuesta :

Memoona

Explanation:

B = μ₀i/2πr

i = 2πrB/μ₀

∵ 16.50 nano Tesla = 1.65×10⁻⁸ Tesla

∵8.10Km = 8100 m

i = 2(3.14)(8100)(1.65×10⁻⁸)/4×3.14×10⁻⁷

i = 668.25 A

So the current carried up or down the funnel of the tornado is 668.25 A.

akande212

Answer:

I = 668A

The solution steps are outline in the attachment below.

B = Iμo/2π

Explanation:

The current is directly proportional to the distance and so for a large distance we got a large current.

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