Respuesta :
The amount of milk that the Professor must add to reach the temperature is 18.09 ml
Step 1 : List the given data
The amount of coffee ordered = 250 mL
Initial temperature of coffee = 95°C
Temperature of milk = 4°C
Final temperature of coffee = 90°C
Specific heat capacity = 4.186 J/g°C
density = 1.0 g/ml
Assumptions :
x = amount of milk added
Initial amount of coffee = ( 250 - x )
Step 2 : Amount of energy released/gained
heat released by coffee ( q1 ) = m*c * ΔT
= 1.0(250 - x ) * 4.86 * ( 90 - 95 ) ------ ( 1 )
heat gained by milk ( q2 ) = m* c * ΔT
where; m = ( density * volume of milk ) , C= 4.186 J/g°C , ΔT = ( 90 - 4 ) = 86°C
q2 = 1.0( x ) * 4.186 * 86 ------- ( 2 )
Step 3: Determine mass of milk needed in milliliters
equate equations (1) and (2) and solve
1.0(250 - x ) * 4.86 * ( 90 - 95 ) = 1.0( x ) * 4.186 * 86
(250 - x ) * 4.86 * - 5 = x * 360
= ( 250 - x ) * -24.3 = 360 x
= 6075 + 24.3 x = 360 x
∴ x ( amount of milk added ) = 6075 / 335.7 = 18.09 mL
Hence the amount of milk added by the professor = 18.09 mL
to learn more : https://brainly.com/question/15682825
