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A proton is in an electric field and has an electric potential energy of 0.5 J. What is the electric potential (voltage) that it experiences?
Could someone explain what I did incorrectly? Thank you!!

A) 3.1 E-19 V <--- I chose this answer originally
B) 1.6 E-19 V
C) 3.1 E18 V <----- I'm pretty sure this is the correct answer?
D) 0.5 V
E) 2.0 V

Respuesta :

AL2006
Here's the magic formula:              1 'volt'  =  1 joule per coulomb .
Everything else is just arithmetic.

So             Voltage  =  (energy) / (charge)

                  Voltage  =   (0.5 J)  /  (1.6 x 10⁻¹⁹)

                                 =    3.125 x 10⁻¹⁸ .

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