A 2.0 kg purse is dropped from the top of the leaning tower of pisa and falls 55m before reaching the ground with a speed of 29 m/s. What was the average force of air resistance?

2.0 kg purse is dropped from the top of the leaning tower of pisa and falls 55m before reaching the ground with a speed of 29 m/s. What was the average force of air resistance

Air Resistance:

is a kind of resistive force that the air applies to a particle or a system of particles when it moves or falls through it. The resistive force is always in opposite direction to the motion of the body.

the average force exerted the air on the purse be F.

From the conservation law of energy, the work done by the air resistance will be equal to the difference between the potential energy and the kinetic energy.

.F*h=mgh-1/2mv2

definition of parameters

m=mass of the purse 2kg

u=initial speed of the purse=om/s

v=final velocity of the purse 29m/s

h=the height of the leaning tower of pisa 55m

g=acceleration due to gravity

F*55=2*9.81*55-0.5*2*29^2

F*55=238.1

F=-4.32N

the opposite direction sows tat it is against the falling purse

Cricetus Cricetus · Answer 2 · 2022-02-11T15:28:52+01:00

The average force ne "-4.32 N".

Air Resistance:

Air resistance would be a force created by air. Whenever an item moves across the sky, the power or attraction operates throughout the opposite direction.

A truck with a flat front will have significant air resistance, but a roadster with something like a streamlined form will always have lesser air resistance, permitting the car to travel quicker.

According to the question,

Mass, m = 2 kg
Initial speed, u = 0 m/s
Final speed, v = 29 m/s
Height, h = 55 m
Acceleration due to gravity, g = 9.8

We know the relation,

→ [tex]F\times h = mgh-\frac{1}{2}mv^2[/tex]

By substituting the values,

[tex]F\times 55= 2\times 9.8\times 55-0.5\times 2\times (29)^2[/tex]

[tex]F\times 55 = 238.1[/tex]

[tex]F = -4.32[/tex] N

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