Answer:
Margin of Error = 9.01%
Explanation:
Given
Sample size, n = 50
Number of regular access = 44
The level of confidence is not stated.
I'll assume a 95% level of confidence, so z* = 1.96
To calculate Margin of error,
First we need to calculate the proportion of those that have regular access and those that don't, as probabilities.
Let P = Probability of those with regular access.
P = 44/50 = 0.88
Let Q = probability of those that don't have regular access
P + Q = 1 --- make Q the subject of formula
Q = 1 - P
Q = 1 - 0.88
Q = 0.12
First, we calculate the standard error
Standard Erro is calculated using the following formula.
A.E = √(PQ/n)
By substituton
S.E = √(0.88*0.12/50)
S.E = 0.045956501172304
Finally,. margin of error is calculated by S.E * z*
= 0.045956501172304 * 1.96
Margin of Error = 0.090074742297716
Margin of Error = 9.01% --- Approximated
