Respuesta :
A) The wall = 32ft * 16ft = 512 square feet.
If one liter of paint covers 100 square feet then you're going to need 6 liter of paint because 5 liters could only cover 500 square feet so it wouldn't be enough. So you get the formula Liter * 0.26417 = gallons and plug in the 6 liter to get 1.58502 gallons
B) From the answer above you can estimate that you would need 2 gallons
C) Remember that you had 6 liters of paint which = 600 square ft. So you have 600 square ft of paint - 512 square ft wall = 88 square ft unused paint. And if one liter = 100 square ft, x liters = 88 square ft. So to get the liter you get the equation 100x=88 --> x=88/100
So the ANSWER is .88 liters of paint will be left remaining in the container.
If one liter of paint covers 100 square feet then you're going to need 6 liter of paint because 5 liters could only cover 500 square feet so it wouldn't be enough. So you get the formula Liter * 0.26417 = gallons and plug in the 6 liter to get 1.58502 gallons
B) From the answer above you can estimate that you would need 2 gallons
C) Remember that you had 6 liters of paint which = 600 square ft. So you have 600 square ft of paint - 512 square ft wall = 88 square ft unused paint. And if one liter = 100 square ft, x liters = 88 square ft. So to get the liter you get the equation 100x=88 --> x=88/100
So the ANSWER is .88 liters of paint will be left remaining in the container.
Find the area (A) of the rectangular wall by multiplying the dimensions,
A = L x W
Substituting,
A = (32 ft) x (16 ft) = 512 ft²
a. (512 ft²) x (1 L / 100 ft²) x (1 gal/ 3.79 L) = 1.35 gal
b. The nearest whole number that is greater than 1.35 is 2. So, 2 containers should be bought.
c. There will remain an amount of 0.65 gallon which is equal to 2.4635 L.
A = L x W
Substituting,
A = (32 ft) x (16 ft) = 512 ft²
a. (512 ft²) x (1 L / 100 ft²) x (1 gal/ 3.79 L) = 1.35 gal
b. The nearest whole number that is greater than 1.35 is 2. So, 2 containers should be bought.
c. There will remain an amount of 0.65 gallon which is equal to 2.4635 L.