The magnitude of the electrostatic force on each one will be ¼ of its initial electrosatic force
Further explanation
Electric charge consists of two types i.e. positively electric charge and negatively electric charge.
There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
[tex]\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }[/tex]
F = electric force (N)
k = electric constant (N m² / C²)
q = electric charge (C)
r = distance between charges (m)
The value of k in a vacuum = 9 x 10⁹ (N m² / C²)
Let's tackle the problem now !
Given:
Q₁' = ½ Q₁
Q₂' = ½ Q₂
Unknown:
F' = ?
Solution:
For this problem we will use a comparison of the two conditions as follows.
[tex]F' : F = k\frac{Q_1'Q_2'}{R^2} : k\frac{Q_1Q_2}{R^2}[/tex]
[tex]F' : F = Q_1'Q_2' : Q_1Q_2[/tex]
[tex]F' : F = (\frac{1}{2}Q_1)(\frac{1}{2}Q_2) : (Q_1Q_2)[/tex]
[tex]F' : F = \frac{1}{4} : 1[/tex]
[tex]F' = \frac{1}{4} F[/tex]
Learn more
- The three resistors : https://brainly.com/question/9503202
- A series circuit : https://brainly.com/question/1518810
- Compare and contrast a series and parallel circuit : https://brainly.com/question/539204
Answer details
Grade: High School
Subject: Physics
Chapter: Static Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces
