Respuesta :

asdfd
(f + g)(x) = 3x^2 + 2x – 1
g(x) = 2x – 2
f(x) = ? ; 3x^2 + 1

Check by Substituting:
3x^2 + 1 + 2x - 2

Simplify:
3x^2 + 2x - 1

Answer:

Option A is correct

[tex]f(x)=3x^2+1[/tex]

Step-by-step explanation:

Use:

[tex](f+g)(x) = f(x)+g(x)[/tex]

Given that:

[tex](f+g)(x)=3x^2+2x-1[/tex] and g(x) = 2x-2

then;

[tex](f+g)(x) = f(x)+g(x)[/tex]

Substitute the given values we have;

[tex]3x^2+2x-1 = f(x)+2x-2[/tex]

Subtract 2x-2 from both sides we get;

[tex]3x^2+2x-1 -2x+2= f(x)[/tex]

Combine like terms;

[tex]f(x) = 3x^2+1[/tex]

Therefore, the function f(x) is, [tex]3x^2+1[/tex]