How could Brent use a rectangle to model the factors of x2 – 7x + 6?

A. He could draw a diagram of a rectangle with dimensions x – 3 and x – 4 and then show the area is equivalent to the sum of x2, –3x, –4x, and half of 12.

B. He could draw a diagram of a rectangle with dimensions x + 7 and x – 1 and then show the area is equivalent to the sum of x2, 7x, –x, and 6.

C. He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.

D. He could draw a diagram of a rectangle with dimensions x – 4 and x + 3 and then show the area is equivalent to the sum of x2, –4x, 3x, and half of –12

He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x^2, –x, –6x, and 6.

The expression is given as:

[tex]x^2 - 7x + 6[/tex]

Expand

[tex]x^2 - 6x - x + 6[/tex]

Factorize

[tex]x(x - 6) -1(x - 6)[/tex]

Factor out x - 6

[tex](x - 1)(x - 6)[/tex]

This means that the factors of [tex]x^2 - 7x + 6[/tex] are x - 1 and x - 6

Hence, the true statement is (c)