interval <-1;1>, which means that this function can take values from interval <-7;-1>. The minimum value is -7.
the min of cos (5pi/6(x+4) = -1
so the min of 4cos 5pi/6(x+4 = -4
so the min of -3 + 4 cos 5pi/6(x+4 = -7
How do you find the minimum value?
If the quadratic equation has a positive term, it also has a minimum value. This minimum can be found by graphing the function or by using one of the two equations. If you have an equation of the form y = ax ^ 2 + bx + c, you can use the equation min = c --b ^ 2 / 4a to find the minimum value.
Rearrange the function using basic algebraic rules and solve the value of x when the derivative is zero. This solution provides the x-coordinates of the vertices of the function where the maximum or minimum values occur. Convert to the original function and solve to find the minimum or maximum value.
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