Answer:
Option B
Step-by-step explanation:
Given: Function [tex]f(x)=6\begin{vmatrix}x-2\end{vmatrix}-5[/tex]
To find: Which point is the vertex of the graph defined by f(x)
Solution : The standard form of absolute function is
[tex]F(x)=a\begin{vmatrix}x-h\end{vmatrix}+k[/tex]
where a is scalar factor and (h,k) is the vertex
Comparing f(x) with standard form a=6 and (h,k)=(2,-5)
Therefore, (2,-5) is the vertex of the graph of [tex]f(x)=6\begin{vmatrix}x-2\end{vmatrix}-5[/tex].(Refer the attached graph)
Hence, option B is correct
