Let Vpa be the velocity of plane with respect to air and Vp and Va be the velocities of plane and air respectively with respect to ground.
Vpa = Vp - Va
Vp = Vpa + Va [all these quantities are vectors]
so by parallelogram law of vector addition
Vp = (Va^2 + Vpa^2 + 2*Va*Vpa*cos120)^(1/2)
Vp^2 = 33^2 + 140^2 - 33*140
Vp^2 = 16096
Vp = 126.763m/s
(2) tan b = (33*sin120)/(140+33/2)
b = 10.34 degrees North of East
(3) component of velocity of plane in east = Vp cos(10.34) = 126.763*1 = 126.7m/s
distance travelled by plane in east = 126.7 * 60*60=456120 m
