Answer:
The value of x and y is 9, 5.
Step-by-step explanation:
[tex]\ The \ Given \ value:\\\\y=\frac{1}{3}x+2........................(i)\\\\ y= \frac{2}{3}x-1 ..........................(ii)\\\\[/tex]
first we subtract the equation (i) to (ii)...
[tex]y=\frac{1}{3}x+2 \\\\y= \frac{2}{3}x-1\\\\0 = \frac{1}{3} x- \frac{2}{3}x + 2+1 \\\\-3= \frac{1-2}{3} x\\\\-3 = - \frac{1}{3}x\\\\ \frac{1}{3} x= 3 \\\\x=9\\\\[/tex]
Put the value of x in equation (i) ...
equation (i)
[tex]y= \frac{1}{3} x+2\\\\y= \frac{1}{3} \times 9+2\\\\y= 3+2\\\\y=5\\[/tex]
