Respuesta :
max cost is the vertex
in the form
y=ax^2+bx+c
the xvalue of the vertex would be -b/2a
we have
C(x)=-0.3x2+600x
a=-0.3
b=600
xvalue of vertex=-600/(2 times -0.3)=1000
that is the numbe rof units
to get the cost, plug it for x
C(1000)=600(1000)-0.3(1000)^2
C(1000)=300,000
the number of units is 1000
the max cost is $300,000
in the form
y=ax^2+bx+c
the xvalue of the vertex would be -b/2a
we have
C(x)=-0.3x2+600x
a=-0.3
b=600
xvalue of vertex=-600/(2 times -0.3)=1000
that is the numbe rof units
to get the cost, plug it for x
C(1000)=600(1000)-0.3(1000)^2
C(1000)=300,000
the number of units is 1000
the max cost is $300,000
Answer:
1000 number of units would produce maximum cost.
Maximum cost = 300000
Step-by-step explanation:
Given that total costs for a company to produce a product x as C(x) = 600x – 0.3x²
At maximum cost derivative of C(x) is zero.
C'(x) = 600 – 0.6x = 0
0.6x = 600
x = 1000
1000 number of units would produce maximum cost.
Maximum cost = C(1000) = 600 x 1000 – 0.3 x 1000² = 300000