Answer:
A. y = [tex]\frac{1}{2}[/tex]x + 10
Step-by-step explanation:
Given;
- The equation y = -7x - 5
- and another equation have a solution of (-2, 9)
If we equate the value of y in the first equation and the value of y in the second equation, then the solution of x should be -2 . Let's test this with equation A:
-7x - 5 = [tex]\frac{1}{2}[/tex]x + 10
-7x - [tex]\frac{1}{2}[/tex]x = 10 + 5
-[tex]\frac{15}{2}[/tex]x = 15
x = (15 × -2) ÷ 15 = -2
*This proves that equation A has the same value of x as our first equation!
Let's test if equation A has a solution; y = 9:
y = [tex]\frac{1}{2}[/tex](-2) + 10 = 9
*This proves that equation A has the same value of y as our first equation!
So the second equation is,
A. y = [tex]\frac{1}{2}[/tex]x + 10
