Answer:
28 ways
Step-by-step explanation:
we know that
Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.
To calculate combinations, we will use the formula
[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex]
where
n represents the total number of items
r represents the number of items being chosen at a time.
In this problem
[tex]n=8\\r=2[/tex]
substitute
[tex]C(8,2)=\frac{8!}{2!(8-2)!}[/tex]
[tex]C(8,2)=\frac{8!}{2!(6)!}[/tex]
simplify
[tex]C(8,2)=\frac{(8)(7)(6!)}{2!(6)!}[/tex]
[tex]C(8,2)=\frac{(8)(7)}{2!}[/tex]
[tex]C(8,2)=\frac{(8)(7)}{(2)(1)}[/tex]
[tex]C(8,2)=28\ ways[/tex]
