has 5 times the mass of the earth and also 5 times the radius. How does the gravitational acceleration on the surface of Driff compare to the gravitational acceleration on the surface of the earth?

Respuesta :

Answer:

The gravitational acceleration on earth is 5 times that on Driff.

Explanation:

The gravitational acceleration on earth is given as:

ge = Gm/r²

Where m = mass of earth, r = radius of earth.

The gravitational acceleration on Driff is given as:

gd = GM/R²

Where M = Mass of Driff, R = radius of Driff.

Since we're told that M = 5m and R = 5r:

gd = G*5m/(5r)²

gd = Gm/5r²

Comparing this to the gravitational acceleration on earth:

ge : gd = Gm/r² : Gm/5r²

ge:gd = 5:1

The gravitational acceleration on earth is 5 times that on Driff.

Answer:

The planet has one-fifth of the gravitational acceleration of the Earth.

Explanation:

Newton's law of gravitational attraction between two bodies of masses [tex]m_1[/tex] and [tex]m_2[/tex] separated by a distance d gives

[tex]F = G\dfrac{m_1m_2}{d^2}[/tex]                       (G is a universal constant)

For any body of mass m on the Earth surface,

[tex]F = G\dfrac{Mm}{R^2}[/tex]

Here, M and R are the mass and the radius of the Earth, respectively.

But this force is the gravitational force on the body.

[tex]F = mg = G\dfrac{Mm}{R^2}[/tex]

[tex]g = G\dfrac{M}{R^2}[/tex]

For a planet with 5 times the mass of Earth and 5 times its radius,

[tex]g_p = G\dfrac{5M}{(5R)^2} = G\dfrac{M}{5R^2} = \dfrac{1}{5}G\dfrac{M}{R^2} = \dfrac{g}{5}[/tex]

Hence the planet has one-fifth of the gravitational acceleration of the Earth.