The decomposition of acetaldehyde is a second order reaction with a rate constant of 4.71 10−8 L/mol/s. What is the instantaneous rate of decomposition of acetaldehyde in a solution with a concentration of 5.55 10−4 M?

Respuesta :

Answer: Rate of decomposition of acetaldehyde in a solution is [tex]1.45\times 10^{-14}mol/Ls[/tex]

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For a reaction : [tex]A\rightarrow products[/tex]

[tex]Rate=k[A]^x[/tex]

k= rate constant

x = order of the reaction = 2

[tex]Rate=4.71\times 10^{-8}L/mol/s\times {5.55\times 10^{-4}M}^2[/tex]

[tex]Rate=1.45\times 10^{-14}[/tex]

Thus rate of decomposition of acetaldehyde in a solution is [tex]1.45\times 10^{-14}mol/Ls[/tex]