Answer:
% oxygen = 47.1 %
% aluminium = 52.9 %
Explanation:
Step 1: Data given
Mass of aluminium = 2.70 grams
Mass of aluminium oxide = 5.10 grams
Step 2: The balanced equation
4Al + 3O2 →2Al2O3
Step 3: Calculate mass of oxygen
The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.
Mass oxygen + mass aluminium = mass aluminium oxide
Mass oxygen + 2.70 grams = 5.10 grams
Mass oxygen = 5.10 grams - 2.70 grams
Mass oxygen = 2.40 grams
Step 4: Calculate percent composition
% oxygen = (mass oxygen / mass aluminium oxide) * 100 %
% oxygen = (2.40 grams / 5.10 grams ) * 100 %
% oxygen = 47.1 %
% aluminium = (mass aluminium / mass aluminium oxide)
% aluminium = (2.70 grams / 5.10 grams ) * 100 %
% aluminium = 52.9 %
47.1 % + 52.9 % = 100 %
The study of chemicals and bonds is called chemistry.
The correct % of oxygen = 47.1 % and % aluminium = 52.9 %
All the data is given in the question as follows:-
According to the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.
Mass oxygen + mass aluminium = mass aluminium oxide
% oxygen = [tex]\frac{mass \ oxygen}{mass\ aluminium \ oxide} * 100 %[/tex]
% oxygen = [tex]\frac{2.40}{5.10 grams} * 100 %[/tex]
% oxygen = 47.1 %
% aluminium = [tex]\frac{2.70}{5.10} * 100 %[/tex]
% aluminium = 52.9 %
The total percentage is 47.1 % + 52.9 % = 100 %.
For more information about the chemical composition, refer to the link:-
https://brainly.com/question/13331538
