Answer:
Explanation:
1) As we know that the work done is the product of force and displacement
It is given as
[tex]W = Fdcos\theta[/tex]
so if the object is not displaced due to the force exerted by the object then the work done by the object must be ZERO
so correct answer is
B) The object has not moved
2) As we know that the work done is the product of force and displacement
It is given as
[tex]W = Fdcos\theta[/tex]
As we know that the wall is not displaced due to applied force so here work done by the prisoner must be zero
D) The prisoner does no work because the wall goes no distance
3) As we know by work energy theorem that work done by all forces is equal to change in its kinetic energy
So we will have
[tex]W_g + W_f = \frac{1}{2} mv^2[/tex]
so we will have
[tex]3(10)(4) + W_f = \frac{1}{2}(3)(3)^2[/tex]
[tex]120 + W_f = 13.5[/tex]
[tex]W_f = -106.5 J[/tex]
now when cart moves half the distance then again using the same
[tex]W_g + W_f = K[/tex]
[tex]K = 3(10)(2) - \frac{106.5}{2}[/tex]
[tex]K = 6.5 J[/tex]