Respuesta :
Answer: The molar concentration of NaOH in the final diluted solution is 0.056 M
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Given mass of NaOH = 4.00 g
Molar mass of NaOH = 40 g/mol
Volume of solution = 5.00 mL
Putting values in above equation, we get:
[tex]\text{Molarity of NaOH solution}=\frac{1.40\times 1000}{40\times 5}\\\\\text{Molarity of NaOH}=7M[/tex]
To calculate the molarity of the diluted solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated NaOH solution
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted NaOH solution
We are given:
[tex]M_1=7M\\V_1=4.00mL\\M_2=?M\\V_2=500mL[/tex]
Putting values in above equation, we get:
[tex]7\times 4.00=M_2\times 500\\\\M_2=\frac{7\times 4.00}{500}=0.056M[/tex]
Hence, the molar concentration of NaOH in the final diluted solution is 0.056 M
