Respuesta :
Given that C and S are balanced, the only unbalanced element is Cl, and it appears alone in the left side, you have to multiply this element by the appropiate coefficient to equal the total number of the same atom in the right side.
So multiply Cl2 by 3 and the balanced equation is
[tex]CS _{2}+3Cl_{2}---\ \textgreater \ CCl_{4}+S_2Cl_2[/tex]
So multiply Cl2 by 3 and the balanced equation is
[tex]CS _{2}+3Cl_{2}---\ \textgreater \ CCl_{4}+S_2Cl_2[/tex]
Explanation:
As the given reaction equation is as follows.
[tex]CS_{2}(l) + Cl_{2}(g) \rightarrow CCl_{4}(l) + S_{2}Cl_{2}(l)[/tex]
So, in order to balance this equation we need to place appropriate coefficients in front of each specie on both reactant and product side.
Hence, multiply [tex]Cl_{2}[/tex] by 3 on the reactant side and the balanced chemical reaction equation will be as follows.
[tex]CS_{2}(l) + 3Cl_{2}(g) \rightarrow CCl_{4}(l) + S_{2}Cl_{2}(l)[/tex]
Thus, we can conclude that the next logical step in balancing the given equation is to place the coefficients.