Answer:
Explanation:
Note: Integer division discards the fraction. Hence the average of 8, 10, 5, 4 is output as 6, not 6.75.
Note: The test cases include four very large input values whose product results in overflow. You do not need to do anything special, but just observe that the output does not represent the correct product (in fact, four positive numbers yield a negative output; wow).
Submit the above for grading. Your program will fail the last test cases (which is expected), until you complete part 2 below.
Part 2: Also output the product and average, using floating-point arithmetic.
Output each floating-point value with three digits after the decimal point, which can be achieved as follows: System.out.printf("%.3f", yourValue);
Ex: If the input is 8, 10, 5, 4, the output is:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int num1;
int num2;
int num3;
int num4;
num1 = scnr.nextInt();
num2 = scnr.nextInt();
num3 = scnr.nextInt();
num4 = scnr.nextInt();
double average_arith = (num1+num2+num3+num4)/4.0;
double product_arith = num1*num2*num3*num4;
int result1 = (int) average_arith;
int result2 = (int) product_arith;
System.out.printf("%d %d\n",result2,result1);
System.out.printf("%.3f %.3f\n",product_arith,average_arith);
}
}
expected output : 1600.000 6.750
Answer:
Complete code with step by step comments for explanation and output results are provided below.
Code with Explanation Part-1:
#include <stdio.h>
int main()
{
// an array of four integers of type int is defined to store the data from the user
int number[4];
// variables of type int to store the result of product and average of numbers
int prod, avg;
printf("Please enter the four integers: ");
// get four integers from the user, %d specifier is used for int
scanf("%d %d %d %d",&number[0],&number[1], &number[2],&number[3] );
// calculate the product of numbers by multiplying them together
prod= number[0]*number[1]*number[2]*number[3];
// calculate the average of numbers by dividing the sum of numbers with total numbers
avg= (number[0]+number[1]+number[2]+number[3])/4;
// print the product and average of the numbers
printf("The product of the four numbers is = %d\n",prod);
printf("The Average of the four numbers is = %d",avg);
return 0;
}
Output Part-1:
Please enter the four integers: 8 10 5 4
The product of the four numbers is = 1600
The Average of the four numbers is = 6
As you can see, by using int type we are not getting the exact value of average.
Code with Explanation Part-2:
#include <stdio.h>
int main()
{
// here we just changed the type from int to float
float number[4];
float prod, avg;
printf("Please enter the four integers: ");
// %f specifier is used for floating point numbers
scanf("%f %f %f %f",&number[0],&number[1], &number[2],&number[3] );
prod= number[0]*number[1]*number[2]*number[3];
avg= (number[0]+number[1]+number[2]+number[3])/4;
// %0.3f is used to show up to 3 decimal digits
printf("The product of the four numbers is = %0.3f\n",prod);
printf("The Average of the four numbers is = %0.3f",avg);
return 0;
}
Output Part-2:
Please enter the four integers: 8 10 5 4
The product of the four numbers is = 1600.000
The Average of the four numbers is = 6.750
As you can see, by using float type we are getting the exact value of average.
