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A vertical scale on a spring balance reads from 0 to 155 N . The scale has a length of 10.0 cm from the 0 to 155 N reading. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.20 Hz .Ignoring the mass of the spring, what is the mass m of the fish?

Respuesta :

Answer:

mass of the fish is 8.11 kg

Explanation:

As we know that the frequency of oscillation of spring block system is given as

[tex]f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}[/tex]

here we know that the reading of scale varies from 0 to 155 N from length varies from x = 0 to x = 10 cm

Now we have

[tex]k = \frac{155}{0.10} N/m[/tex]

[tex]k = 1550 N/m[/tex]

so now we have

[tex]2.20 = \frac{1}{2\pi}\sqrt{\frac{1550}{m}}[/tex]

[tex]m = 8.11 kg[/tex]

so mass of the fish is 8.11 kg

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