Answer:
[tex]\frac{x^{2} }{16 } +\frac{y^{2} }{25 } =1[/tex]
Step-by-step explanation:
General equation of an eclipse
[tex]\frac{x^{2} }{a^{2} } +\frac{y^{2} }{b^{2} } =1[/tex]
From what I can see on the graph, b = 5. Therefore, b^2 = 25
So the equation will be the top one.
[tex]\frac{x^{2} }{4^{2} } +\frac{y^{2} }{5^{2} } =1[/tex]
[tex]\frac{x^{2} }{16 } +\frac{y^{2} }{25 } =1[/tex]
