Respuesta :

znk

Answer:

[tex]\large \boxed{\text{6.7 mol NH}_{3}}[/tex]  

Explanation:

           N₂ + 3H₂⟶ 2NH₃

n/mol:           10

The molar ratio is 2 mol NH₃:3 mol H₂.

[tex]\text{Moles of NH}_{3} = \text{ 10 mol H}_{2} \times \dfrac{\text{2 mol NH}_{3}}{\text{3 mol H}_{2}}= \textbf{6.7 mol NH}_{\mathbf{3}}\\\\\text{The reaction produces $\large \boxed{\textbf{6.7 mol NH}_{\mathbf{3}}}$}[/tex]

Haileymack037

Answer:

6.7

Explanation:

Well, where is your stoichiometric equation that represents ammonia synthesis…?

12N2(g)+32H2(g)⟶NH3(g)

And so  23×10.4∙mol=?? moles of ammonia

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