Answer:
P(x = 12) = 0.1144.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they have received the vaccination, or they have not. The probability of an adult receiving the vaccination is independent from other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.
This means that [tex]p = 0.7[/tex]
Sample of 20 adults
This means that [tex]n = 20[/tex]
Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.
This is [tex]P(X = 12)[/tex].
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144[/tex]
P(x = 12) = 0.1144.