Respuesta :
Answer:
Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
Step-by-step explanation:
Step 1: Factor
256x^4y^2−y^2
y^2(256x^4 - 1)
y^2(16x^2 - 1)(16x^2 + 1)
y^2(4x + 1)(4x - 1)(16x^2 + 1)
Answer: Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.