Answer:
Rate of first bus = 72 mph
Rate of second bus = 62 mph
Step-by-step explanation:
let first bust travels at x mph
then, 2nd but will travel at ( x - 10) mph
distance travelled by first bus in 2 hours = 2x
distance travelled by 2nd but in 2 hours = 2( x- 10) = 2x - 20
distance between the two is 268 miles
so we can write
2x + 2x - 20 = 268
4x = 288
x = 288 / 4 = 72 mph
rate of first bus = 72 mph
and second bus = 72 - 10 = 62 mph
Answer: speed of slower bus is 62 mph.
Speed of faster bus is 72 mph
Step-by-step explanation:
Let x represent the the speed of the slower bus.
One bus travels 10 miles per hour slower than the other. It means that the speed of the faster bus is (x + 10) mph
Distance = speed × time
The 2 buses meet in 2 hours.
Distance travelled by the slower bus in 2 hours is 2 × x = 2x
Distance travelled by the faster bus in 2 hours is
2(x + 10)
By the time they meet, they would have travelled 268 miles. It means that
2x + 2(x + 10) = 268
2x + 2x + 20 = 268
4x + 20 = 268
4x = 268 - 20
4x = 248
x = 248/4
x = 62 mph
Speed of the faster bus is
x + 10 = 62 + 10 = 72 mph
