Consider the given quadratic equation [tex]50-x^2=0[/tex]
[tex]x^2-50=0[/tex]
Comparing the given quadratic equation to the general equation [tex]ax^2+bx+c=0[/tex], we get a= 1, b=0 and c= -50
So, the solution to the quadratic equation is given by:
[tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]
[tex]x = \frac{-0 \pm \sqrt{0^2-4(1)(-50)}}{2}[/tex]
[tex]x = \frac{\pm \sqrt{200}}{2}[/tex]
[tex]x = \pm \sqrt2 (5)[/tex]
[tex]x = \pm 5\sqrt2[/tex]
So, the solutions to the given quadratic equation are [tex]x = \pm 5\sqrt2[/tex].
