Answer:
The length of one diagonal is 122 units.
Step-by-step explanation:
Quadrilateral LMNO has diagonals that intersect at point P.
LMNO is a parallelogram.
P is intersection point of diagonals.
In parallelogram, diagonals are bisect each other.
Therefore, LP=NP because NL is a diagonal of parallelogram and P is mid point of NL.
6x - 5 = 4x + 17
6x - 4x = 17 + 5
2x = 22
x = 11
LN = 2(4x+17) Put x=11
LN = 2(4(11) + 17)
= 2(61)
= 122
Hence, The length of one diagonal is 122 units.
