Answer:
The value of P(A|B) is [tex]\frac{15}{16}[/tex].
Step-by-step explanation:
Given information: [tex]P(A\cap B)=\frac{3}{4}[/tex], [tex]P(B)=\frac{4}{5}[/tex]
Conditional probability
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]
[tex]P(A|B)=\frac{\frac{3}{4}}{\frac{4}{5}}[/tex]
[tex]P(A|B)=\frac{3}{4}\times \frac{5}{4}[/tex]
[tex]P(A|B)=\frac{15}{16}[/tex]
Therefore the value of P(A|B) is [tex]\frac{15}{16}[/tex].
