Respuesta :
The first book can be any one of the 5.
For each of those . . .
The 2nd book can be any one of the remaining 4.
For each of those ...
The 3rd book can be any one of the remaining 3.
For each of those . . .
The 4th book can be either of the remaining 2.
For each of those . . .
The 5th book is the last one remaining.
Total number of ways to arrange the 5 books is
(5 · 4 · 3 · 2 · 1) = 120 .
Cross off alphabetically ascending (1 way), and alphabetically
descending (1 way), and you're left with (120 - 2) = 118 ways.
For each of those . . .
The 2nd book can be any one of the remaining 4.
For each of those ...
The 3rd book can be any one of the remaining 3.
For each of those . . .
The 4th book can be either of the remaining 2.
For each of those . . .
The 5th book is the last one remaining.
Total number of ways to arrange the 5 books is
(5 · 4 · 3 · 2 · 1) = 120 .
Cross off alphabetically ascending (1 way), and alphabetically
descending (1 way), and you're left with (120 - 2) = 118 ways.
Hence in 118 ways arrangement of volume
What is Permutation?
When the order of the arrangements counts, a permutation is a mathematical technique for determining the number of alternative arrangements in a collection. Choosing only a few things from a list in a specific order is a common mathematical issue.
How to solve?
Given A–C, D–F, G–J, K–N, and O–Z they can be arranged in 5! ways
Hence5!=5*4*3*2*1=120 but it excludes ascending or descending
⇒120-2 =118
hence option B -118 is correct .
Learn more about Permutation https://brainly.com/question/1216161
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