What is the f of x over the g of x when f(x) = − 2x3 + x2 + 16x − 15 and g(x) = x + 3?

Question

contestada

Respuesta :

apologiabiology apologiabiology · Answer 1 · 2016-07-09T02:59:45+02:00

easy
f(x)/g(x)
replace
(-2x^3+x^2+16x-15)/(x+3)
you can simlify this to get
-2x^2+7x-5

Answer Link

lisboa lisboa · Answer 2 · 2019-06-29T04:35:20+02:00

Answer:

[tex]\frac{f(x)}{g(x)}=-2x^2+7x-5[/tex]

Step-by-step explanation:

[tex]f(x)=-2x^3 + x^2 + 16x -15[/tex]

[tex]g(x)= x+3[/tex]

Now we need to find f(x) divide by g(x)

[tex]\frac{f(x)}{g(x)}[/tex]

Plug in f(x) and g(x)

[tex]\frac{f(x)}{g(x)}=\frac{-2x^3 + x^2 + 16x -15}{x+3}[/tex]

LEts divide it using long division

-2x^2+7x-5

-----------------------------------------

[tex]x+3[/tex] [tex]-2x^3 + x^2 + 16x -15[/tex]

[tex]-2x^3-6x^2[/tex]

------------------------------------------------(subtract)

[tex]7x^2+16x[/tex]

[tex]7x^2+21x[/tex]

---------------------------------------------------(subtract)

[tex]-5x - 15x[/tex]

-------------------------------------------(subtract)

0

[tex]\frac{f(x)}{g(x)}=-2x^2+7x-5[/tex]