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if the distance between two objects is decreased to one fourth of the original distance how will the decrease change the force of attraction between the objects

Respuesta :

olemakpadu
F = GMm/r²

The relationship between F and r is an inverse one. So if the distance r decreases, to 1/4 the original distance:

Let  F α 1/r²

F = k/r²

or    F₂ / F₁ = (r₁ / r₂)²

If r is decreased to 1/4,  

F₂ / F₁ = (r₁ / r₂)²

F₂ / F₁ = (r₁ / (1/4r₁) )²

F₂ / F₁ = (4)²

F₂ / F₁ = 16

F₂ = 16F₁

The new force of attraction would be 16 times the former value.

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