The distance between (-6, 8) and (-3, 9) is approximately 9.055.
Let [tex]P_{1}[/tex] and [tex]P_{2}[/tex] be distinct points on cartesian plane, the straight line distance between these points ([tex]d[/tex]) is determined by means of Pythagorean theorem:
[tex]d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex] (1)
Where:
- [tex]x_{1}[/tex], [tex]x_{2}[/tex] - x-Coordinates of the endpoints.
- [tex]y_{1}[/tex], [tex]y_{2}[/tex] - y-Coordinates of the endpoints.
If we know that [tex]P_{1}(x,y) = (-6, 8)[/tex] and [tex]P_{2}(x,y) = (-3, 9)[/tex], then the straight line distance is:
[tex]d = \sqrt{[-3-(-6)]^{2}+(9-8)^{2}}[/tex]
[tex]d \approx 9.055[/tex]
The distance between (-6, 8) and (-3, 9) is approximately 9.055.
We kindly invite to know this question on straight line distances: https://brainly.com/question/1156725
