Answer: 0.5 seconds for 4 ft and 2 seconds for 64 ft
d=16t^2
4=16t^2
/16 /16
t^2=1/4
t=1/2
0.5 seconds for 4 ft
64 = 16t^2
/16 /16
4=x^2
x=2
2 seconds for 64 ft
The time (in seconds) that it will take a golf ball to drop to the ground from a height of 4 feet is 0.5 second and from a height of 64 feet is 2 seconds.
You can simply replace those variables with the value you know of them and then operate on those values to get a final value. This is the result of that expression at those values of the considered variables.
It is given that:
[tex]d = 16t^2 \: \rm feet[/tex] is the distance from which if the ball is dropped freely, then it lands on the ground in t seconds.
Expressing t in terms of d:
[tex]t^2 = \dfrac{d}{16}\\t = \pm \sqrt{\dfrac{d}{16}}\\\\t = \dfrac{\sqrt{d}}{4} \: \rm sec.[/tex] (as time cannot be negative, unless we're talking about the time before the ball falls).
This is the time it will take a ball to fall on the ground if it starts falling d feet above the ground.
Thus, the time (in seconds) that it will take a golf ball to drop to the ground from a height of 4 feet is 0.5 second and from a height of 64 feet is 2 seconds.
Learn more about evaluating a function at a value here:
https://brainly.com/question/2753269
